(3y^2-3x^2)=0

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Solution for (3y^2-3x^2)=0 equation:


Simplifying
(3y2 + -3x2) = 0

Reorder the terms:
(-3x2 + 3y2) = 0

Remove parenthesis around (-3x2 + 3y2)
-3x2 + 3y2 = 0

Solving
-3x2 + 3y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y2' to each side of the equation.
-3x2 + 3y2 + -3y2 = 0 + -3y2

Combine like terms: 3y2 + -3y2 = 0
-3x2 + 0 = 0 + -3y2
-3x2 = 0 + -3y2
Remove the zero:
-3x2 = -3y2

Divide each side by '-3'.
x2 = y2

Simplifying
x2 = y2

Take the square root of each side:
x = {-1y, y}

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